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0=x^2-5x+6x-30
We move all terms to the left:
0-(x^2-5x+6x-30)=0
We add all the numbers together, and all the variables
-(x^2-5x+6x-30)=0
We get rid of parentheses
-x^2+5x-6x+30=0
We add all the numbers together, and all the variables
-1x^2-1x+30=0
a = -1; b = -1; c = +30;
Δ = b2-4ac
Δ = -12-4·(-1)·30
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-11}{2*-1}=\frac{-10}{-2} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+11}{2*-1}=\frac{12}{-2} =-6 $
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